Respuesta :

Eduard22sly

Answer:

Option C. 1.60×10¯²¹ J

Explanation:

The following data were obtained from the question:

Frequency (f) = 2.40×10¹² Hz

Energy (E) =..?

We can obtain the energy of the photon of the infrared light by applying the following formula:

Energy (E) = Planck's constant (h) × frequency (f)

E = hf

Frequency (f) = 2.40×10¹² Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =..?

E = 6.63×10¯³⁴ × 2.40×10¹²

E = 1.60×10¯²¹ J

Thus, the energy of the photon of the infrared light which has a frequency of 2.40×10¹² Hz is 1.60×10¯²¹ J

According to the law of energy, it states that energy can never be created nor be destroyed. It can only transfer from one thing to another.

These are the various type of energy:-

  • Heat energy
  • Wind energy
  • Light energy
  • Water energy

We can obtain the energy of the photon of the infrared light by applying the following formula:

Energy (E) = Planck's constant (h) × frequency (f)  

[tex]E = hf[/tex]

After putting the value:-

[tex]E = 6.63 * 10^3^4 * 2.40*10^1^2[/tex]

After solving the equation, the energy is:-

E = 1.60×10¯²¹ J

Thus, the energy of the photon of the infrared light which has a frequency of 2.40×10¹² Hz is 1.60×10¯²¹J

For more information, refer to the link:-

https://brainly.com/question/18461965

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