Answer:
Step-by-step explanation:
i'll explain how to do 9), it is the same process for the rest
y = 2x - 1
thus the value of 'y' should be the same as the result of '2x - 1'
when x = 5, 2x - 1 = 2(5) - 1 = 9, Thus (x, y) = (5, 9)
when x = 2, 2x - 1 = 2(2) - 1 = 3 Thus (x, y) = (2, 3)
when x = 0, 2x - 1 = 2(0) - 1 = 1 Thus (x, y) = (0, 1)
so in the table we have
x 2x - 1 y (x, y)
5 9 9 (5, 9)
2 3 3 (2, 3)
0 1 1 (0, 2)
we can now plot these values on a graph to look like so
