Michael is training to join the Army and runs to the left with a constant
velocity of 2 m/s. If he starts at Om, what is his position after 5 seconds?
Don't forget units and directions if appropriate.
Your answer
[tex]his \: position \:is \: his \: distance \: from \: the \: \\ point \: of \: motion \: and \: is \: given \: by : \\ v = \frac{s}{t} \\ s = vt =2 \times 5 \\ s = 10 \: m.[/tex]
