In this simulation, you will be exploring the relationship between temperature and pressure while keeping volume
constant. Click here to begin. Select the Explore box. Answer the questions as you perform the steps.
1. Raise and push down the pressure pump handle to add gas molecules to the container. The initial temperature is
300 K (27º) and the pressure has a range of 5.4-6.2 atm. Notice the pressure values change as the particles
collide with the wall.
2. Click on the bucket to raise the temperature of the container to approximately 400 K (127°C). What happened to
the pressure?
Approximately what pressure range did you observe?
3. Click on the bucket to reduce the temperature to approximately 200 K (-73°C). What happened to the pressure?
Approximately what pressure did you observe?
4. What gas law mathematically shows the relationships between temperature and pressure?

Respuesta :

Answer:

increased, 7.5-8.3 atm; decreased, 3.5-4.3 atm; Gay-Lussac's Law

Explanation:

1. The collision of gas molecules, results in the pressure increases.

2. The pressure of the system with an increase in the temperature has been 7.2-8.2 atm.

3. The pressure of the system with a decrease in the temperature has been 3.6-4.1 atm.

4. The relationship between the molecules has been given by Gay-Lussac's Law.

The relationship between the temperature and pressure has been given in the gaseous molecules with the ideal gas equation.

1. The temperature has been directly proportional to the temperature. Thus, with an increase in pressure, there has been an increase in temperature and vice versa.

With the collision of the gas molecules with the wall, there has been the liberation of the energy that increases the temperature. The increase in temperature mediates the increase in pressure.

Thus, with the collision of gas molecules, the pressure increases.

2. The relationship between the pressure and temperature has been given as:

[tex]\dfrac{P1}{T1}=\dfrac{P2}{T2}[/tex]

The initial temperature [tex]T1=300\;\text K[/tex]

Final temperature [tex]T2=400\;\text K[/tex]

Initial pressure, [tex]P1=5.4-6.2\;\text {atm}[/tex]

Final pressure, [tex]P2[/tex]

Substituting the values for calculating P2 as:

[tex]\rm \dfrac{5.4-6.2\;atm}{300\;K}=\dfrac{P2}{400\;K}\\\\\textit P2 = \dfrac{5.4-6.2\;atm}{300\;K}\;\times\;400\;K\\\\\textit{P}2=7.2-8.2\;atm[/tex]

The pressure of the system with an increase in the temperature has been 7.2-8.2 atm.

3. The pressure with the reduction of temperature has been given by :

[tex]\dfrac{P1}{T1}=\dfrac{P2}{T2}[/tex]

The initial temperature [tex]T1=400\;\text K[/tex]

Final temperature [tex]T2=200\;\text K[/tex]

Initial pressure, [tex]P1=7.2-8.2\;\text {atm}[/tex]

Final pressure, [tex]P2[/tex]

Substituting the values for calculating P2 as:

[tex]\rm \dfrac{7.2-8.2\;atm}{400\;K}=\dfrac{P2}{200\;K}\\\\\textit P2 = \dfrac{7.2-8.2\;atm}{400\;K}\;\times\;200\;K\\\\\textit{P}2=3.6-4.1\;atm[/tex]

The pressure of the system with a decrease in the temperature has been 3.6-4.1 atm.

4. The relationship between the molecules has been given by Gay-Lussac's Law. The law states that pressure has been directly proportional to the absolute temperature of the system.

For more information about pressure of gas molecules, refer to the link:

https://brainly.com/question/15863086