Answer:
[tex]a=2\ m/s^2[/tex]
Explanation:
Given that,
Mass of a worker, m = 80 kg
When the elevator begins to move, the scale reads 960 N
We need to find the magnitude of the elevator's acceleration. The net force acting on it is given by :
[tex]F_s-F_g=ma\\\\F_s-mg=ma\\\\960-80(10)=80a\\\\160=80a\\\\a=2\ m/s^2[/tex]
So, the magnitude of the elevator's acceleration is [tex]2\ m/s^2[/tex].