A 0.52-kg block sits on a lab table. There is a forward force of 2.63 N and a force backwards of 0.67 N. What is the acceleration of the block?

Respuesta :

Answer:

a = 3.77 m/s²

Explanation:

Given:

m = 0.52-kg

F = 2.63 N - 0.67 N = 1.96 N (Net Force)

Unknown:

a or acceleration

Formula and solution:

a = F/m

a = 1.96 kg.m/s² ÷ 0.52 kg

Final Answer:

a = 3.77 m/s²

There are the same unit in the solution which is kg so we cancel it then the rest which is m/s² combine it in the quotient of 1.96 kg.m/s² or N and 0.52 kg which is 3.769 then round off to nearest hundredths so the final answer is 3.77 m/s²