Answer:
The speed of the box just as it hits the ground is 5.8 m/s
Explanation:
Given;
initial velocity of the box, u = 2 m/s
height of the table, h = 1.5 m
The speed of the box, just before it hits the ground is given by;
v² = u² + 2gh
v² = (2)² + 2 x 9.8 x 1.5
v² = 4 + 29.4
v² = 33.4
v = √33.4
v = 5.8 m/s
Therefore, the speed of the box just as it hits the ground is 5.8 m/s
