Answer:
b) [tex] b) 3x(x − 3)(x2 + 3x + 9)[/tex]
Step-by-step explanation:)
Take a factor [tex] 3x[/tex] from the expression. You're left with [tex] 3x(x^3-27) = 3x(x^3-3^3)[/tex] which is a difference of cubes. Cube differences are decomposed as a product as [tex] (a-b)(a^2+ab+b^2)[/tex] (an easy way to remember that is that you already have the minus in the first bracket to cancel out terms, so they're all pluses in the second).
