Answer:
The speed of the aircraft = 81.2310 m/s
Explanation:
Using Bernoulli equation: (p1/p) + (V1^2/2) + gh1 = (p2/p) + (V2^2/2) + gh2
Since the relationship highlights the relationship between the pressure in the fluid and the velocity of the aircraft at a given height.
Where g = acceleration due to gravity
p1, p2 = the pressure at point 1 and the pressure at point 2 respectively
p = the density of the fluid
The density of air at the height of 3000 m = 0.9093 kg/m^3
V1, V2 = velocity at point 1 and velocity at point 2 res[ectively
h1, h2 = height at point 1, height at point 2 respectively
height is constant, which means h1 = h2
The velocity at point 2 is not stated which makes it zero
So from the Bernoulli equation above, we now have:
(p1/ p) + (V1^2/2) = p2/p
Making V1 the subject
V1 = √(2(p2 - p1)) /(p)
V1 = √(2(3000) / (0.9093)
V1 = √(2 x 3,299.24117)
V1 = √6,598.4823
V1 = 81.2310 m/s
