Answer:
enantiomeric excess = 68%
Explanation:
Enantiomeric excess is a value used to determine the purity of chiral molecules. It is possible to determine enantiomeric excess (ee) using:
ee = R - S / R + S * 100
Where R is the mass (In this case percentage) of the R enantiomer and S of the S enantiomer.
Replacing with values of the problem:
ee = 84% - 16% / 84% + 16% * 100
ee = 68%
