Respuesta :

apologiabiology
this would be easer to factor
(x+3)(x+4)=0
x+3=0
x+4=0

x=-3 and -4

bu tif want quadratic

in form
ax^2+bx+c=0

x=[tex] \frac{-b+/- \sqrt{b^2-4ac} }{2a} [/tex]

ax^2+bx+c=0
1x^2+7x+12=0
a=1
b=7
c=12
x=[tex] \frac{-b+/- \sqrt{b^2-4ac} }{2a} [/tex]
x=[tex] \frac{-7+/- \sqrt{7^2-4(1)(12)} }{2(1)} [/tex]
x=[tex] \frac{-7+/- \sqrt{49-48} }{2} [/tex]
x=[tex] \frac{-7+/- \sqrt{1} }{2} [/tex]
x=[tex] \frac{-7+/- 1}{2} [/tex]
x=-6/2 or -8/2
x=-3 or -4

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