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Suppose Sine (x) = four-fifths and cos(x) < 0. What is the value of cos(2x)?

Negative StartFraction 14 Over 25 EndFraction
Negative StartFraction 7 Over 25 EndFraction
StartFraction 7 Over 25 EndFraction
StartFraction 14 Over 25 EndFraction

Suppose Sine x fourfifths and cosx lt 0 What is the value of cos2x Negative StartFraction 14 Over 25 EndFraction Negative StartFraction 7 Over 25 EndFraction St class=

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xxbobdabearxx

Answer:

B.-7/25

Step-by-step explanation:

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The required value of cos(2x) is -7/25. Option B is correct.

sinx = 4/5
cosx < 0

What is trigonometry?

Trigonometry is the study of angles in mathematics.

Here,
cos(2x) = 1-2sin²x
           = 1 - 2 x 4²/5²
           =  1 - 32/25
cos(2x) =  -7/25

Thus, the required value of cos(2x) is -7/25.

Learn more about trigonometry here:
https://brainly.com/question/26719838

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