Answer:
[tex](x + y) {}^{2} \\ = x {}^{2} + 2xy + y {}^{2} \\ = x {}^{2} + y {}^{2} + 2xy \\ = 23 + 2 \times 6 \\ = 23 + 12 \\ = 35 \\ \\ therefore \: the \: value \: \\ of \: (x + y) {}^{2} is \: 35.[/tex]
35 is the correct answer.....
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Thank you ☺️
