Answer:
1. 0.015
2. 0.135
Explanation:
Given that
[tex]P (B| A)[/tex] = 15%
P(A) = 10%
P(B) = 5%
a. The calculation of probability an employee will experience a lost-time accident in both years is shown below:-
[tex]P(A\cap B) = P (B| A)P (A)[/tex]
now, we will put the values into the above formula
= 0.15 × 0.10
= 0.015
2. The calculation of probability an employee will experience a lost-time accident over the two-year period is shown below:-
[tex]P(A\cup B) = P(A) + P(B) - P(A\cap B)\\[/tex]
= 0.10 + 0.05 - 0.015
= 0.135