Geetard
contestada

Find the discriminant of the quadratic equation x2 + 14x + 8 = 0 and use it to determine the number and types of solutions.

b2 − 4ac

228; Two real solutions
228; One real solution
164; Two nonreal solutions
164; Two real solutions

Respuesta :

Leora03

Answer:

(4th option) 164; Two real solutions

Step-by-step explanation:

Please see the attached picture for the full solution.

b² -4ac > 0

➣2 real and distinct roots

b² -4ac = 0

➣ 1 repeated root/ 2 real and equal roots

b² -4ac < 0

➣ No real roots

*Roots is another name for the solutions of a quadratic equation.

Ver imagen Leora03

The discriminant of the quadratic equation is 164 and two real solutions are present.

Discriminant

Mathematically, the discriminant of the quadratic equation is [tex]D=b^2-4ac[/tex].

How to determine the discriminant of a quadratic equation?

The given quadratic equation is [tex]x^2+14x+8=0[/tex].

Here, b=14 and c=8.

So, the discriminant is-

[tex]D=(14)^2-4\times 1\times 8\\=196-32\\=164[/tex]

As the discriminant is positive so, the roots of the solutions are real and distinct.

Thus, the discriminant of the quadratic equation is 164 and two real solutions are present.

Learn more about discriminant here- https://brainly.com/question/15884086

#SPJ2

Otras preguntas