Remove all perfect squares from inside the square root. Assume b is positive

Answer:
4b[tex]\sqrt{5}[/tex]
Step-by-step explanation:
Factor 80[tex]b^{2}[/tex].
80[tex]b^{2}[/tex] = 4 * 4 * 5 * b * b
Since there are two 4s and bs, they can be taken out of the square. (Because if you put a square root over 4 squared or b squared, you would get 4 or b.)
Now you are left with 4b[tex]\sqrt{5}[/tex].