Answer:
1. Displacement = 3.29 km
b. His direction is [tex]33.21^{o}[/tex] north of east
2. Average velocity is 1.10 km/h
b. His direction is [tex]33.21^{o}[/tex] north of east
3. Average speed = 1.52 km/h
Explanation:
1. Displacement = [tex]\sqrt{x^{2} + y^{2} }[/tex]
= [tex]\sqrt{1.8^{2} + 2.75^{2} }[/tex]
= [tex]\sqrt{10.8025}[/tex]
= 3.2867
Displacement = 3.29 km
b. tan θ = [tex]\frac{y}{x}[/tex]
θ = [tex]tan^{-1} \frac{1.8}{2.75}[/tex]
= [tex]tan^{-1}[/tex]0.6546
= 33.20878
θ = [tex]33.21^{o}[/tex]
His direction is [tex]33.21^{o}[/tex] north of east
2. Average velocity = [tex]\frac{displacement}{time}[/tex]
= [tex]\frac{3.29}{3}[/tex]
= 1.09667
Average velocity is 1.10 km/h
b. His direction is [tex]33.21^{o}[/tex] north of east.
3. average speed = [tex]\frac{total distance}{time}[/tex]
total distance covered = 1.80 km + 2.75 km
= 4.55 km
Average speed = [tex]\frac{4.55}{3}[/tex]
= 1.5167
Average speed = 1.52 km/h
