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the length of a rectangle is 24 feet more than the width. The perimeter of the rectangle is 88 feet. What is the length and width of this rectangle?

Respuesta :

altavistard

Answer:

W = 10 ft

Step-by-step explanation:

Represent the length by L and the width by W.  Then L = W + 24.

The perimeter is P = 2W + 2L, or 88 ft.  Thus, after substituting L = W + 24,

88 ft = 2W + 2(W + 24), or

88 = 2W + 2W + 48, or, after reduction,

44 = 2W + 24, or

2W = 20, and so W = 10 ft

onyebuchinnaji

The length of the rectangle is 34 feet.

The given parameters;

  • perimeter of the rectangle, P = 88 feet.
  • let the width of the rectangle = w
  • then, the length of the rectangle, L = 24 + w

The length of the rectangle is calculated as follows;

P = 2(L+ w)

P = 2(24 + w + w)

P = 2(24 + 2w)

88 = 48 + 4w

subtract 48 from both sides of the equation;

88 - 48 = 4w

40 = 4w

w = 10

Now, solve for the length;

L = 24 + w

L = 24 + 10

L = 34 feet

Thus, the length of the rectangle is 34 feet.

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