Respuesta :
Given Equation:
[tex] \huge \purple {\rm { {x}^{2} + kx - 12 = 0}} [/tex]
Value:
[tex] \huge \purple {\rm {x = 4}} [/tex]
To Find:
[tex] \huge \purple {\rm {The \: value \: of \: k.}} [/tex]
Solution:
[tex] \huge \purple {\rm { {(4)}^{2} + k(4) - 12 = 0}} [/tex]
[tex] \huge \purple {\rm {or, \: 16 + 4 k - 12 = 0}} [/tex]
[tex] \huge \purple {\rm {or, \: 4k = - 4}} [/tex]
[tex] \huge \purple {\rm {or, \: k = \frac{ - 4}{4} = - 1}} [/tex]
Answer:
[tex] \huge \purple {\sf {The \: value \: of \: k \: is \: -1}} [/tex]
Answer:
k = - 1
Step-by-step explanation:
Given that x = 4 is a root then, substitute x = 4 into the equation.
4² + 4k - 12 = 0
16 + 4k - 12 = 0, that is
4k + 4 = 0 ( subtract 4 from both sides )
4k = - 4 ( divide both sides by 4 )
k = - 1