Answer:
6[tex]\sqrt{15}[/tex]
Step-by-step explanation:
Using the rule of radicals
[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex] , then
[tex]\sqrt{60}[/tex]
= [tex]\sqrt{4(15)}[/tex]
= [tex]\sqrt{4}[/tex] × [tex]\sqrt{15}[/tex] = 2[tex]\sqrt{15}[/tex] thus
3[tex]\sqrt{60}[/tex]
= 3 × 2[tex]\sqrt{15}[/tex]
= 6[tex]\sqrt{15}[/tex]
