Answer:
[tex] d = 9.4 units [/tex] (nearest tenth)
Step-by-step explanation:
Given the distance formula, [tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex], distance between (-4, 5) and (4, 0) is calculated as follows:
Let [tex] (-4, 5) = (x_1, y_1) [/tex]
[tex] (4, 0) = (x_2, y_2) [/tex]
[tex] d = \sqrt{(4 - (-4))^2 + (0 - 5)^2} [/tex]
[tex] d = \sqrt{(8)^2 + (- 5)^2} [/tex]
[tex] d = \sqrt{64 + 25} [/tex]
[tex] d = \sqrt{89} [/tex]
[tex] d = 9.4 units [/tex] (nearest tenth)
