Respuesta :

Alfpfeu

Answer:

Step-by-step explanation:

Hello,

[tex]\dfrac{x^2-100}{x+10}=\dfrac{x^2-10^2}{x+10}=\dfrac{(x-10)(x+10)}{x+10}=x-10\\\\\text{so, we can conclude.}\\\\\displaystyle \lim_{x\rightarrow-10} \ \dfrac{x^2-100}{x+10}=-10-10=-20[/tex]

Thanks

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