BigMooch
contestada

Find three consecutive integers whose sum is 216. (Hint: if n represents the smallest of the three integers, n + 1 and n + 2 represent
the other two numbers.)

Respuesta :

xKelvin

Answer:

71, 72, 73

Step-by-step explanation:

So we want to find three consecutive integers that equal 216.

Let the first integer be n.

Then the second integer is n+1, and the third integer is n+2.

Thus:

[tex]n+(n+1)+(n+2)=216[/tex]

Combine like terms:

[tex]3n+3=216[/tex]

Subtract 3 from both sides:

[tex]3n=213\\[/tex]

Divide 3 from both sides:

[tex]n=71[/tex]

So, the first term is 71.

And the other two is 72 and 73.

And we are done :)

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