Answer:
[tex]\sqrt{61}[/tex] ≈ 7.81
Step-by-step explanation:
Calculate the distance d using the distance formula
d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = P1(- 4, - 3) and (x₂, y₂ ) = P2(2, 2)
d = [tex]\sqrt{(2+4)^2+(2+3)^2}[/tex]
= [tex]\sqrt{6^2+5^2}[/tex]
= [tex]\sqrt{36+25}[/tex]
= [tex]\sqrt{61}[/tex] ≈ 7.81 ( to 2 dec. places )
The distance between P₁ = (-4, -3) and P₂ = (2, 2) is 7.810
The distance between two points is the shortest length between two points.
Given P₁ = (-4, -3) and P₂ = (2, 2) are the two points
is [tex]\sqrt({x_{2}-x_{1})^{2} )+({y_{2}-y_{1})^{2} }[/tex]
Here, (x₁, y₁) = (-4, -3) and (x₂, y₂) = (2, 2)
[tex]\sqrt({2}-(-4_}))^{2} )+({2}-(-3)})^{2}[/tex]
=[tex]\sqrt({(2+4)^{2} } +(2+3)}^{2})}[/tex]
= [tex]\sqrt({6^{2} } +5^{2})[/tex]
= [tex]\sqrt({36}+25)[/tex]
= [tex]\sqrt{61}[/tex]
= 7.810
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