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2. A train moving at 15 m/s slows down, and eventually stops after 5
seconds. What is the acceleration of the train?
G: Vi =
Vf=
U:
E: Formula
S: Substitute
S: Solve

Respuesta :

Answer:

Acceleration, a = -3 m/s²

Explanation:

Given that,

Initial speed, u = 15 m/s

Final speed, v = 0

Time, t = 5 s

We need to find the acceleration of the train. It is equal to the change in velocity divided by time taken. So,

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{0-15\ m/s}{5\ s}\\\\a=-3\ m/s^2[/tex]

So, the acceleration of the train is 3 m/s² and it is deaccelerating.

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