Answer:
All (a,b) that satisfy a.b < 0 will make that statement false
Step-by-step explanation:
It is only right when:
|a-b| = |a| - |b|
<=> ( |a-b| ) ^ 2 = ( |a| - |b| ) ^ 2
<=> a^2 - 2ab + b^2 = a^2 - 2.|ab| + b^2
<=> ab = |ab|
<=> ab ≥ 0
So, when ab < 0, it's wrong
