please help!! I just started college

Answer:
(r. q) (7) = [tex] \pm 220[/tex]
(q.r) (7) = [tex] \pm 220[/tex]
Step-by-step explanation:
[tex]q(x) = {x}^{2} + 6 \\ q(7) = {7}^{2} + 6 = 49 + 6 = 55\\ r(x) = \sqrt{x + 9} \\ r(7) = \sqrt{7 + 9} = \sqrt{16} = \pm 4 \\ \\ (r.q)(7) = r(7).q(7) = \pm 4 \times 55 = \pm220 \\ \\ (q.r)(7) = q(7).r(7) = 55 \times \pm 4 = \pm220 [/tex]