Answer:
The answer is "[tex]y=\frac{c}{1+a}[/tex]".
Step-by-step explanation:
Given:
[tex]\bold{y=\frac{c}{1+ae^{-rx}}}[/tex]
For the y-intercept, the value x is =0
[tex]y=\frac{c}{1+ae^{-r \times 0}}[/tex]
[tex]y=\frac{c}{1+ae^{0}}[/tex]
[tex]\therefore e^0 = 1[/tex]
[tex]y=\frac{c}{1+a\times 1}}[/tex]
[tex]\boxed{y=\frac{c}{1+a}}[/tex]
