Light emitted by element X passes through a diffraction grating that has 1200 slits/mm. The interference pattern is observed on a screen 77.0 cm behind the grating. First-order maxima are observed at distances of 58.0 cm , 65.4 cm , and 94.5 cm from the central maximum. What are the wavelengths of light emitted by element X?

Respuesta :

Answer:

500 nm, 530 nm, 650 nm

Explanation:

Let's say that there is diffraction grating observed with a slit spacing of s. Respectively we must determine the angle θ which will help us determine the 3 wavelengths ( λ ) of the light emitted by element X. This can be done applying the following formulas,

s( sin θ ) = m [tex]*[/tex] λ, such that y = L( tan θ ) - where y = positioning, or the distance of the first - order maxima, and L = constant, of 77 cm

Now the grating has a slit spacing of -

s = 1 / N = 1 / 1200 = 0.833 [tex]*[/tex] 10⁻³ mm

The diffraction angles of the " positionings " should thus be -

θ = tan⁻¹ [tex]*[/tex] ( 0.58 / 0.77 ) = 37°,

θ = tan⁻¹ [tex]*[/tex] ( 0.654 / 0.77 ) = 40°,

θ = tan⁻¹ [tex]*[/tex] ( 0.945 / 0.77 ) = 51°

The wavelengths of these three bright fringes should thus be calculated through the formula : λ = s( sin θ ) -

λ = 0.833 [tex]*[/tex] 10⁻³ [tex]*[/tex] sin( 37° ) = ( 500 [tex]*[/tex] 10⁻⁹ m )

λ = 0.833 [tex]*[/tex] 10⁻³ [tex]*[/tex] sin( 40° ) = ( 530 [tex]*[/tex] 10⁻⁹ m )

λ = 0.833 [tex]*[/tex] 10⁻³ [tex]*[/tex] sin( 51° ) = ( 650 [tex]*[/tex] 10⁻⁹ m )

Wavelengths : 500 nm, 530 nm, 650 nm

This question will be solved using the "grating equation".

The wavelengths of the light emitted by element X are:

"1. 6.654 x 10⁻⁷ m = 665.4 nm

2. 6.349 x 10⁻⁷ m = 634.9 nm

3. 5.262 x 10⁻⁷ m = 526.2 nm"

The diffraction grating equation is given as follows:

[tex]m\lambda = d Sin\ \theta[/tex]

where,

m = order of maxima = 1

λ = wavelength of light = ?

d = grating element = [tex]\frac{1}{no.\ of\ slits\ per\ unit\ length} = \frac{1}{1200\ slits/mm}[/tex]

d =  (8.33 x 10⁻⁴ mm/slit)(1 m/ 1000 mm) = 8.33 x 10⁻⁷ m/slit

θ = angle of diffraction = [tex]tan^{-1}(\frac{L}{y})[/tex]

where,

L = distance of grating from the screen = 77 cm

y = distance of maxima from central maxima

Hence, the general equation after substituting constant values becomes:

[tex]\lambda = (8.33\ x\ 10^{-7}\ m/slits)\ Sin(tan^{-1}(\frac{77\ cm}{y}))[/tex]

FOR y = 58 cm:

[tex]\lambda = (8.33\ x\ 10^{-7}\ m/slits)\ Sin(tan^{-1}(\frac{77\ cm}{58\ cm}))[/tex]

λ = 6.654 x 10⁻⁷ m = 665.4 nm

FOR y = 65.4 cm:

[tex]\lambda = (8.33\ x\ 10^{-7}\ m/slits)\ Sin(tan^{-1}(\frac{77\ cm}{65.4\ cm}))[/tex]

λ = 6.349 x 10⁻⁷ m = 634.9 nm

FOR y = 94.5 cm:

[tex]\lambda = (8.33\ x\ 10^{-7}\ m/slits)\ Sin(tan^{-1}(\frac{77\ cm}{94.5\ cm}))[/tex]

λ = 5.262 x 10⁻⁷ m = 526.2 nm

The attached picture shows the arrangement of the light rays in a diffraction grating.

Learn more about diffraction grating here:

https://brainly.com/question/17012571?referrer=searchResults

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