Answer:
The answer is B.
Step-by-step explanation:
First you have to find the angle of ATB. Given that ∠TAB and ∠TBA have the same angle and the total angle in a triangle is 180°. So you have to subtract :
∠TAB + ∠TBA + ∠ATB = 180°
∠ATB + 62° + 62° = 180°
∠ATB + 124° = 180°
∠ATB = 180° - 124°
∠ATB = 56°
A tangent to a circle will always be 90°, so ∠TAO and ∠TBO are 90°. In a quadrilateral, total angles is 360°. So the angle of AOB is :
∠ATB + ∠TAO + ∠TBO + ∠AOB = 360°
56° + 90° + 90° + ∠AOB = 360°
236° + ∠AOB = 360°
∠AOB = 360° - 236°
∠AOB = 124°
