Answer:
The height of the objects are the same after 2 seconds.
Step-by-step explanation:
In order to calculate at which time both objects have the same height we need to find the value of t that makes both equations equal. Therefore:
[tex]-t^2 + 3t = -t + 4\\t^2 - 3t - t + 4 = 0\\t^2 - 4t + 4 = 0\\t_{1,2} = \frac{-(-4) \pm \sqrt{(-4)^2 - 4*1*4}}{2*1} = \frac{4 \pm \sqrt{16 - 16}}{2}\\t_{1,2} = \frac{4}{2} = 2[/tex]
The height of the objects are the same after 2 seconds.
