Answer:
[tex]2\frac{1}{10}[/tex]
Step-by-step explanation:
Use BIDMAS
B = Brackets
I = Indices
D = Division
M = Multiplication
A = Addition
S = Subtraction
[tex]\frac{6}{7} * (\frac{3}{8} /\frac{15}{10} +2\frac{1}{5} )[/tex]
→ Work out the division sum inside of the brackets
[tex]\frac{3}{8} /\frac{15}{10} =\frac{3}{8} *\frac{10}{15} =\frac{30}{120} =\frac{1}{4}[/tex]
→ Write out new sum
[tex]\frac{6}{7} *(\frac{1}{4} +2\frac{1}{5} )[/tex]
→ Work out the sum of the addition inside the bracket
[tex]\frac{1}{4} +2\frac{1}{5} =\frac{1}{4} +\frac{11}{5} =\frac{5}{20} +\frac{44}{20 } =\frac{49}{20} =2\frac{9}{20}[/tex]
→ Write out new sum
[tex]\frac{6}{7} *2\frac{9}{20}[/tex]
→ Solve
[tex]\frac{6}{7} *2\frac{9}{20}=\frac{6}{7} *\frac{49}{20} =\frac{294}{140} =\frac{147}{70} = \frac{21}{10} =2\frac{1}{10}[/tex]
