Respuesta :

It should be this: 1s22s22p63s23p5

Answer:

Option B

[tex] {1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{5} [/tex]

Explanation:

In writing the electronic configuration for chlorine the first two electron will go in the 1s orbital.Since 1s can hold two electrons the next 2 electrons for chlorine go in the 2s orbital.The next 6 electrons will go in the 2p orbital.The p orbital can hold up to 6 electrons.We'll put six in the 2p orbital and then put the next 2 electron in the 3e.Since the 3s is now full.We'll move to 3p where we place remaining 5 electrons...

Thus,the electron configuration of chlorine(Cl) is

[tex] {1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{5} [/tex]

Hope this helps....

Good luck on your assignment...