Answer:
[tex]\boxed{ \ \sf5(\dfrac{1}{5})^{-x}\ }[/tex]
Step-by-step explanation:
As this is a reflection over the y axis we are looking for a function g so that
g(-x)=f(x) for x real
it gives g(x)=f(-x)
so the correct answer is
[tex]5(\dfrac{1}{5})^{-x}[/tex]
we can write it as
[tex]\dfrac{5}{5^x} \ or \ \dfrac{1}{5^{x-1}} \ as \ well[/tex]
you can see the graphs below
hope this helps
