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The chemical reaction of the reactants, NaCH3COO and HCl, is written as follows:

NaCh3COO + HCl = NaCl + CH3COOH

To balance it, the number of atoms of an element in one side should be equal to the other side. By looking at the reaction, I believe it is already balanced. They have 1 is to 1 ratios.

Answer:

[tex]CH_3COONa~+~HCl~->~CH_3COOH~+~NaCl[/tex]

Explanation:

This is an acid-base reaction in which the HCl is the acid and the [tex]CH_3COONa[/tex] is the base.

In the balanced reaction, we will have a double replacement reaction. In which the cation of  [tex]CH_3COONa[/tex] (in this case [tex]Na^+[/tex]) will be exchanged by the hydronium ion [tex]H^+[/tex] from the [tex]HCl[/tex]. Similarly the anion of [tex]HCl[/tex] ([tex]Cl^-[/tex] ) would bond with the cation [tex]Na^+[/tex] to form [tex]NaCl[/tex].

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