Answer:
Step-by-step explanation:
(a + b)(a-b) = a² - b²
i² = -1
(1 + i)(1-i) = 1² - i² = 1 - (-1) = 1 +1 = 2
[tex]\frac{(1+i)(1-i)}{2-3i}=\frac{2}{2-3i}\\\\=\frac{2*(2+3i)}{(2-3i)(2+3i)}\\\\=\frac{2*2+2*3i}{2^{2}-(3i)^{2}}\\\\=\frac{4+6i}{4-3^{2}*i^{2}}\\\\\frac{4+6i}{4-9*(-1)}\\\\=\frac{4+6i}{4+9}\\\\=\frac{4+6i}{13}\\\\=\frac{4}{13}+\frac{6}{13}i[/tex]
