Respuesta :
Answer:
- tomatoes acre(s) = 120
- lettuce acre(s) = 0
- carrots acre(s)= 0
- profit $ = $360,000
- all 120 acres are used
Step-by-step explanation:
You can write the linear system model as follows. Let t, l, c represent acres of tomatoes, lettuce, and carrots, respectively. The we have ...
t + l + c ≤ 120 . . . . . constraint on available land
5t +4l +2c ≥ 480 . . requirement for spending on fertilizer
4t +2l +2c ≤ 600 . . constraint on available labor
t ≥ 0; l ≥ 0; c ≥ 0 . . requirement for non-negative acres
Then the objective function (profit) is ...
p = 3000t +1400l +400c
The linear programming problem is to maximize p subject to the above constraints.
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Any of a variety of solvers can find the solution to this problem. That solution is ...
(t, l, c) = (120, 0, 0) and p = 360,000
In summary ...
tomatoes acre(s) = 120 (all available acres are used)
lettuce acre(s) = 0
carrots acre(s) = 0
profit $ = $360,000
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Additional comments
This solution suggests that it can be found simply by examining the profit associated with each unit of resource.
profit per acre is maximized for tomatoes, at $3000 per acre
profit per fertilizer dollar is maximized for tomatoes, at $600 per dollar
profit per labor hour is maximized for tomatoes, at $750 per hour
That is, the profit per acre is maximized for tomatoes, regardless of the resource being considered. Thus it make sense to put all of the acreage in tomatoes. At $5 per acre for fertilizer, we use $600 worth of fertilizer. At 4 hours per week per acre, we use 480 hours of labor, so not all available labor is used.