Respuesta :
Answer:
10.42% probability that you randomly select a milk chocolate first, replace it, and then select a white chocolate
Step-by-step explanation:
Since the chocolate is replaced, the first selection and the second are independent of each other.
Independent events:
If two events, A and B, are independent.
[tex]P(A \cap B) = P(A)P(B)[/tex]
In this question:
Event A: Selecting a milk chocolate first.
Event B: Selecting a white chocolate.
5+4+3 = 12 chocolates. Of those, 5 are milk.
This means that [tex]P(A) = \frac{5}{12}[/tex]
3 are white.
This means that [tex]P(B) = \frac{3}{12} = \frac{1}{4}[/tex]
What is the probability that you randomly select a milk chocolate first, replace it, and then select a white chocolate?
[tex]P(A \cap B) = P(A)P(B) = \frac{5}{12}*\frac{1}{4} = \frac{5}{48} = 0.1042[/tex]
10.42% probability that you randomly select a milk chocolate first, replace it, and then select a white chocolate
