quintusangelo quintusangelo

30-05-2020
Mathematics

contestada

Tan θ =
[tex] \sqrt{13} \div \sqrt{2} [/tex]

Respuesta :

mahesh11 mahesh11

30-05-2020

Answer:

Step-by-step explanation:

Tan θ = [tex]\sqrt{13} \div \sqrt{2}[/tex] = 2.5495

Therefore θ = [tex]Tan^{-1}[/tex] (2.5495) =68.5832°

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Smartteacherlearner Smartteacherlearner

30-05-2020

Answer:

Tan θ = 2.5495097...

Answer Link

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