Consider the total ionic equation below.

Ba2+ + 2NO3 + 2Na+ + Co3 —BaCO3 + 2Na+ + 2NO3

Which is the net ionic equation for the reaction?

O Ba2+ + C03 —> BaCO3

© 2Na+ + co} → Na2CO3

NO3 + Na* —> NaNO3

O Ba2+ + 2NO3 →→ Ba(NO3)2

Respuesta :

Answer:

Ba²⁺ + CO₃²⁻ → BaCO₃

Explanation:

A net ionic equation is a way to write a chemical reaction in which you list only the species that are participating in the reaction.

For the reaction:

Ba²⁺ + 2NO₃ + 2Na⁺ + CO₃²⁻ → BaCO₃ + 2Na⁺ + 2NO₃

As you can see, NO₃ and Na⁺ are not participating in the reaction. Thus, net ionic equaation is:

Ba²⁺ + CO₃²⁻ → BaCO₃

Complete Question

Consider the total ionic equation below.

[tex]Ba^{2+} + 2NaO_3^{1 -} + 2Na^{+} + CO_3^{2-} ----> BaCO_3 + 2Na^{+} + 2NO_3^{1-}[/tex]

Which is the net ionic equation for the reaction?

A [tex]Ba^{2+} _{(aq)} + CO_3 ^{2-} _{(aq)} ----> BaCO_3_{(s)}[/tex]

B [tex]2Na^+ + CO_2 ----> Na2CO3[/tex]

C [tex]NO3 + Na ^ + ----> NaNO3[/tex]

D   [tex]Ba_2^+ + 2NO3 ----> Ba(NO3)2[/tex]

Answer:

Option A is the correct option

Explanation:

The given ionic equation is

       [tex]Ba^{2+} + 2NaO_3^{1 -} + 2Na^{+} + CO_3^{2-} ----> BaCO_3 + 2Na^{+} + 2NO_3^{1-}[/tex]

Looking at this complete ionic equation we see that [tex]Na^{+1} \ and \ NO_3^{1-}[/tex] did not change in the reaction so they will not be included in the net ionic equation so the net ionic equation becomes

         [tex]Ba^{2+} _{(aq)} + CO_3 ^{2-} _{(aq)} ----> BaCO_3_{(s)}[/tex]