Write the equation of a line in standard form that has x-intercept (P,0) and y-intercept (0,R).

A: Rx- Py = PR

B: Rx + Py = PR

C: Px - Ry = -PR

D: Px - Ry = PR

PLEASE ONLY ANSWER IF YOU ARE 100% SURE

Respuesta :

Answer:

[tex]Rx+Py=RP[/tex]

Step-by-step explanation:

The points on the straight line are (P, 0) and (0, R).

The slope would be

[tex]m=\frac{R-0}{0-P}=-\frac{R}{P}[/tex]

And [tex]b=R[/tex], because the y-intercept is at (0, R).

So, the equation of this line would be

[tex]y=-\frac{R}{P} x+R[/tex]

Where we multiply the equation by [tex]P[/tex]

[tex]Py=-Rx+RP[/tex]

Therefore, the equation that represents this line is

[tex]Rx+Py=RP[/tex]

So, the right answer is B.

The equation of a line in a standard form has x-intercept (P,0) and y-intercept (0,R) is (Py + Rx = RP) and this can be determined by using the point-slope form.

Given :

  • x-intercept (P,0)
  • y-intercept (0,R)

The point-slope form can be used to determine the equation of a line in a standard form that has x-intercept (P,0) and y-intercept (0,R).

The point-slope form of the line is given by the equation:

[tex]\dfrac{y-y_1}{x-x_1}=\dfrac{y_2-y_1}{x_2-x_1}[/tex]   --- (1)

where [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are the points on the line.

Now, put the values of points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] in the equation (1).

[tex]\rm \dfrac{y-0}{x-P}=\dfrac{R-0}{0-P}[/tex]

[tex]\rm \dfrac{y-0}{x-P}=-\dfrac{R}{P}[/tex]

Py = -Rx + RP

Py + Rx = RP

The equation of a line in a standard form has x-intercept (P,0) and y-intercept (0,R) is (Py + Rx = RP). Therefore, the correct option is B).

For more information, refer to the link given below:

https://brainly.com/question/6539370