Answer:
(D)Multiply the previous value by 2
Step-by-step explanation:
[tex]\left|\begin{array}{c|c}$Powers of 2&Value\\2^{-5}&\frac{1}{32}\\\\2^{-4}&\frac{1}{16}\\\\2^{-3}&\frac{1}{8}\\\\2^{-2}&\frac{1}{4}\\\\ 2^{-1}&\frac{1}{2}\\\\2^{0}&1\end{array}\right|[/tex]
From the given table, we observe that the negative power of 2 reduces by 1 at each step.
[tex]2^{-5}X2=2^{-4}\\2^{-4}X2=2^{-3}\\2^{-3}X2=2^{-2}[/tex]
Therefore, as the exponents increase, we multiply the previous value by 2 to obtain the next value.
The correct option is D.
