Cars lose value the farther they are driven. A random sample of 111111 cars for sale was taken. All 111111 cars were the same make and model. A line was fit to the data to model the relationship between how far each car had been driven and its selling price. Which of these linear equations best describes the given model? Choose 1 answer: Choose 1 answer: (Choice A) A \hat y=\dfrac12x+40 y ^ ​ = 2 1 ​ x+40y, with, hat, on top, equals, start fraction, 1, divided by, 2, end fraction, x, plus, 40 (Choice B) B \hat y=-x+40 y ^ ​ =−x+40y, with, hat, on top, equals, minus, x, plus, 40 (Choice C, Checked) C \hat y=-\dfrac14x+40 y ^ ​ =− 4 1 ​ x+40y, with, hat, on top, equals, minus, start fraction, 1, divided by, 4, end fraction, x, plus, 40 Based on this equation, estimate the price of a car that had been driven 565656 thousand kilometers. \$dollar sign 14 thousand dollars

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Answer:

C) y=-(1/4)x+40

The price of a car that had been driven 56 thousand kilometers is estimated as $27,500

Step-by-step explanation:

In the figure attached, the plot is shown. y represents price (thousands of dollars) and x represents kilometers driven (in thousands)

The y-intercept of the trend line is located at (0, 40)

The line also pass through (20, 35), then its slope is: (35 - 40)/(20 - 0) = -1/4

Replacing into the equation with x = 56, we get:

y=-(1/4)(50)+40 = 27.5

that is, 27.5*1000 = $27,500

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Answer:

C and 26 thousand dollars

Step-by-step explanation: