Respuesta :

[tex]\dfrac{4x}{5}-12=20\ \ \ \ |add\ 12\ to\ both\ sides\\\\\dfrac{4x}{5}=32\ \  \ \ |multiply\ both\ sides\ by\ 5\\\\4x=160\ \ \ \ |divide\ both\ sides\ by\ 4\\\\\boxed{x=40}[/tex]

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