Answer : The volume of gas occupy at [tex]1.00\times 10^2^oC[/tex] is, 1.25 L
Explanation :
Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.
Mathematically,
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1\text{ and }T_1[/tex] are the initial volume and temperature of the gas.
[tex]V_2\text{ and }T_2[/tex] are the final volume and temperature of the gas.
We are given:
[tex]V_1=1.00L\\T_1=25.0^oC=(25.0+273)K=298K\\V_2=?\\T_2=1.00\times 10^2^oC=((1.00\times 10^2)+273)K=373K[/tex]
Putting values in above equation, we get:
[tex]\frac{1.00L}{298K}=\frac{V_2}{373K}\\\\V_2=1.25L[/tex]
Therefore, the volume of gas occupy at [tex]1.00\times 10^2^oC[/tex] is, 1.25 L
