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Suppose you are titrating vinegar, which is an acetic acid solution of unknown strength, with a sodium hydroxide solution according to the equation

H
C
2
H
3
O
2
+
N
a
O
H
⟶
H
2
O
+
N
a
C
2
H
3
O
2

If you require 32.22 mL of 0.1943 M
N
a
O
H
solution to titrate 10.0 mL of
H
C
2
H
3
O
2
solution, what is the concentration of acetic acid in the vinegar?

Respuesta :

pstnonsonjoku

Answer:

0.0626 M

Explanation:

Equation of the reaction

CH3COOH(aq) + NaOH(aq) ---------> CH3COONa(aq) + H2O

Concentration of acid CA= ???

Concentration of base CB= 0.1943 M

Volume of acid VA= 10.0ml

Volume of base VB= 32.22 ml

Number of moles of acid NA= 1

Number of moles of base NB= 1

From

CA= CB VB NA/VA NB

Hence ;

CA= 0.1943 M × 32.22 ml × 1/10.0ml ×1

CA= 0.0626 M

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