Your pump empties the water from a swimming pool in 8 hours. When your friend's pump is used together with your pump, the pool is emptied in 2
hours and 40 minutes. How long (in hours) does it take your friend's pump to empty the pool when working alone?

Respuesta :

Answer:

4 Hr.

Step-by-step explanation:

Given,

Your pump alone can empties the water in = 8 hrs

With the help of friend pump it take = 2.67 hr

time taken by friends to empty the whole tank = t = ?

We have,

[tex]\dfrac{1}{8}+\dfrac{1}{t}= \dfrac{1}{2.67}[/tex]

[tex]\dfrac{1}{t}= \dfrac{1}{2.67}-\dfrac{1}{8}[/tex]

[tex]\dfrac{1}{t}=0.2499[/tex]

[tex]t = \dfrac{1}{0.2499}[/tex]

[tex]t = 4\ hrs[/tex]

Time taken to empty the tank by the friends pump alone is equal to 4 Hr.

The time taken should be 4 hours.

Calculation of the time taken:

Since Your pump empties the water from a swimming pool in 8 hours. When your friend's pump is used together with your pump, the pool is emptied in 2 hours and 40 minutes.

So, here the time taken be

[tex]1\div 8 + 1\div t = 1\div 2.67\\\\1\div t = 1\div 2.67 - 1\div 8\\\\1\div t = 0.2499[/tex]

t = 4 hours

hence, The time taken should be 4 hours.

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