Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)
To find the slope(m), use the slope formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex] And plug in the two points on the line
(-4, -4) = (x₁, y₁)
(4, -2) = (x₂, y₂)
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\frac{-2-(-4)}{4-(-4)}[/tex] (two negative signs cancel each other out and become positive)
[tex]m=\frac{-2+4}{4+4}[/tex]
[tex]m=\frac{2}{8}[/tex] Simplify the fraction
[tex]m=\frac{1}{4}[/tex] Now that you know the slope, substitute/plug it into the equation
y = mx + b
[tex]y=\frac{1}{4} x+b[/tex] To find b, plug in either of the points into the equation, it doesn't matter which, then isolate/get the variable "b" by itself. I will use (4, -2)
[tex]-2=\frac{1}{4}(4)+b[/tex]
-2 = 1 + b Subtract 1 on both sides to get "b" by itself
-3 = b
[tex]y=\frac{1}{4} x-3[/tex] Your answer is A
