Answer: The Molarity of the Chloride ion in a 5M [tex]AlCl_3[/tex] solution is 15 M
Explanation:
Molarity is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n= moles of solute
[tex]V_s[/tex] = volume of solution in ml
[tex]AlCl_3\rightarrow Al^{3+}+3Cl^-[/tex]
Now as 1 mole of [tex]AlCl_3[/tex] gives 3 moles of [tex]Cl^-[/tex]
5 moles of [tex]AlCl_3[/tex] gives =[tex]\frac{3}{1}\times 5=15[/tex] moles of [tex]Cl^-[/tex]
Thus Molarity of the Chloride ion in a 5M [tex]AlCl_3[/tex] solution is 15 M
