Answer:
Image distance, v = 4.67 cm
Explanation:
We have,
Height of the object, h = 24.8 cm
Height of the formed image, h' = -3.09 cm
Object distance, u - -37.5 cm
It is required to find the image distance. Lens formula is :
[tex]\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}[/tex]
Using formula of magnification,
[tex]m=\dfrac{v}{u}=\dfrac{h'}{h}[/tex]
v is image distance
[tex]v=\dfrac{uh'}{h}\\\\v=\dfrac{-37.5\times (-3.09)}{24.8}\\\\v=4.67\ cm[/tex]
So, the image distance is 4.67 cm.
